C++标准库里面没有像java的String类中提供的字符分割函数split ,着实不方便。
1.简洁高效的方法(不过只能包含一个分隔符):
1 #include2 #include 3 #include 4 using namespace std; 5 6 void SplitString(const string& s, vector & v, const string& c) 7 { 8 string::size_type pos1, pos2; 9 pos2 = s.find(c);10 pos1 = 0;11 while(string::npos != pos2)12 {13 v.push_back(s.substr(pos1, pos2-pos1));14 15 pos1 = pos2 + c.size();16 pos2 = s.find(c, pos1);17 }18 if(pos1 != s.length())19 v.push_back(s.substr(pos1));20 }21 22 int main(){23 string s = "a,b,c,d,e,f";24 vector v;25 SplitString(s, v,","); //可按多个字符来分隔;26 for(vector ::size_type i = 0; i != v.size(); ++i)27 cout << v[i] << " ";28 cout << endl;29 //输出: a b c d e f30 }
当处理有空格的字符串时,还是很有用的!!
2.可包含多个分隔符的实现方式
1 #include2 #include 3 #include 4 using namespace std; 5 6 vector split(const string &s, const string &seperator){ 7 vector result; 8 typedef string::size_type string_size; 9 string_size i = 0;10 11 while(i != s.size()){12 //找到字符串中首个不等于分隔符的字母;13 int flag = 0;14 while(i != s.size() && flag == 0){15 flag = 1;16 for(string_size x = 0; x < seperator.size(); ++x)17 if(s[i] == seperator[x]){18 ++i;19 flag = 0;20 break;21 }22 }23 24 //找到又一个分隔符,将两个分隔符之间的字符串取出;25 flag = 0;26 string_size j = i;27 while(j != s.size() && flag == 0){28 for(string_size x = 0; x < seperator.size(); ++x)29 if(s[j] == seperator[x]){30 flag = 1;31 break;32 }33 if(flag == 0)34 ++j;35 }36 if(i != j){37 result.push_back(s.substr(i, j-i));38 i = j;39 }40 }41 return result;42 }43 44 int main(){45 // string s = "a,b*c*d,e";46 string s;47 getline(cin,s);48 vector v = split(s, ",*"); //可按多个字符来分隔;49 for(vector ::size_type i = 0; i != v.size(); ++i)50 cout << v[i] << " ";51 cout << endl;52 //输出: a b c d e53 }
3.用C语言中的strtok 函数来进行分割
1 #include2 #include 3 4 int main(){ 5 char s[] = "a,b*c,d"; 6 const char *sep = ",*"; //可按多个字符来分割 7 char *p; 8 p = strtok(s, sep); 9 while(p){10 printf("%s ", p);11 p = strtok(NULL, sep);12 }13 printf("\n");14 return 0;15 }16 //输出: a b c d
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